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At 10^(@)C, the osmotic pressure of urea solution is 500 mm. The solution is diluted and the temperature is raised to 25^(@)C when the osmotic pressure is found to be 105.3 mm. Calculate the extent of dilution. |
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Answer» Solution :Suppose initially the volume of solution `=V_(1)` `"Given"T=10+273K = 283 K, pi=(500)/(7760)" atm"` `pi="CRT"=(pi)/(V)=RT""therefore""(500)/(600)=(n)/(V_(1))Rxx283"…(i)"` After dilution, suppose volume of solution `=V_(2)` `"Given"T=25+273K=298K, pi=(105.3)/(760)" atm"` `therefore""(105.3)/(760)=(n)/(V_(2))Rxx298"(n = no. of moles which remains same)...(ii)"` Dividing eqn. (i) by eqn. (ii) `(500)/(105.3)=(V_(2))/(V_(1))xx(283)/(293)"or"(V_(2))/(V_(1))=(500)/(105.3)xx(298)/(283)=5"or"V_(2)=5V_(1)` Thus, solution has been diluted 5 times. |
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