At 1.70 atm , a sample of gas takes up 4.25 L. If the pressure in the

1.	At 1.70 atm , a sample of gas takes up 4.25 L. If the pressure in the gas is increased to 2.40 atm. what the new volume be of the gas. Temperature is constant.
Answer» Given: Initial pressure(p1) = 1.70 atm. Initial volume(v1)= 4.25 L. Final pressure(p2) = 2.40 atm. Temperature is constant. To find: The final volume of the gas(V2). SOLUTION: Initial pressure(p1) = 1.70 atm. Initial volume(v1)= 4.25 L. Final pressure(p2) = 2.40 atm. Temperature is constant. Final volume(v2) = ? From the FORMULA we get that, p1v1 = p2v2 [At constant temperature.] ⇒ (1.70×4.25) = (2.40×v2) ⇒ (2.40×v2) = (1.70×4.25) ⇒ (2.40×v2) = 7.225 ⇒ v2 = (7.225÷2.40) ⇒ v2 = 2.89 L ∴ The final volume of the gas will be 2.89 L. Answer: The final volume of the gas will be 2.89 L.

At 1.70 atm , a sample of gas takes up 4.25 L. If the pressure in the gas is increased to 2.40 atm. what the new volume be of the gas. Temperature is constant.

Answer»

The final volume of the gas(V2).

Initial pressure(p1) = 1.70 atm.

Initial volume(v1)= 4.25 L.

Final pressure(p2) = 2.40 atm.

Temperature is constant.

Final volume(v2) = ?

From the FORMULA we get that,

p1v1 = p2v2 [At constant temperature.]

⇒ (1.70×4.25) = (2.40×v2)

⇒ (2.40×v2) = (1.70×4.25)

⇒ (2.40×v2) = 7.225

⇒ v2 = (7.225÷2.40)

⇒ v2 = 2.89 L

∴ The final volume of the gas will be 2.89 L.

The final volume of the gas will be 2.89 L.