Assuming the expression for the pressure p exerted by an ideal gas ,prove that the kinetic energy per unit volume of gas is 3/2p.

Assuming the expression for the pressure p exerted by an ideal gas ,pr

1.	Assuming the expression for the pressure p exerted by an ideal gas ,prove that the kinetic energy per unit volume of gas is 3/2p.
Answer» tion:Correct option isB[ 32 ] RD kinetic energy per unit VOLUME of a gasKinetic energy of the GAS K= 21 mv rms2 Rms velocity of gas molecules v rms = m3RT ∴ K= 21 m. m3RT = 23 RTFrom ideal gas equation, RT=PV⟹ K= 23 PVThus we get PRESSURE of the gas P= 32 VK

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Assuming the expression for the pressure p exerted by an ideal gas ,prove that the kinetic energy per unit volume of gas is 3/2p.

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