assuming the earth to be perfectly homogeneous sphere of radius 6400 k

1.	assuming the earth to be perfectly homogeneous sphere of radius 6400 km find the value of acceleration due to gravity at the latitude of 60 degree if its value at the poles is 9.8 metre per second square . Angular velocity of a the earth is about its axis is given by ω=7.27X 10 raise to power minus- 5
Answer» ANSWER: In Original it is 9.81 But according to question according to questionit is 9.78 Explanation: GIVEN: R=6400km angle= 60° g=9.8m/s^2 angular velocity w=7.27×10^-5 g at 60° =? sol^n: g• = g - w^2r but [email PROTECTED] r=6400×sin60° r=6400×0.867 r=5449km so g•=9.8 - (7.27×10^-5)^2×5449×10^3 {I.e 1km=1000m} g•=9.8 - 0.0287 *g•=9.772*

assuming the earth to be perfectly homogeneous sphere of radius 6400 km find the value of acceleration due to gravity at the latitude of 60 degree if its value at the poles is 9.8 metre per second square . Angular velocity of a the earth is about its axis is given by ω=7.27X 10 raise to power minus- 5

Answer»

ANSWER:

In Original it is 9.81 But according to question

according to questionit is 9.78

Explanation:

GIVEN: R=6400km

angle= 60°

g=9.8m/s^2

angular velocity w=7.27×10^-5

g at 60° =?

sol^n:

g• = g - w^2r

but

[email PROTECTED]

r=6400×sin60°

r=6400×0.867

r=5449km

g•=9.8 - (7.27×10^-5)^2×5449×10^3

{I.e 1km=1000m}

g•=9.8 - 0.0287

g•=9.772

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g•=9.772

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