1.

Assuming that sea water is and aqueous solution of NaCI, its density is 1.025 g/mL at 20^(@)C and NaCI concerntration is 3.5% (by mass). The normality of sea water is :

Answer»

0.65 N
0.68 N
0.66 N
0.61 N

Solution :MASS of NACI =3.5 g
Mass of solution= 100 g
`"Volume of solution"="Mass"/"DENSITY" `
`=((100G))/((1.025g m L^(-1)))=97.56 m`
`"Equivalent mass of NaCI"=58.5 g equiv^(-1)`
`"Normality of solution (N)"=("No. of g equiv"^(-1)solute)/("Volumeof solution in litres")`
`((3.5g)//(58.5 "g equiv"^(-1)))/(97.56//1000L)`
` =0.61 "equiv L"^(-1)=0.61 N`


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