1.

Assuming that Raoult's Law is followed, what wolud be the vapour pressue of a solution formed when 40 g of sugar density is 1g/mL.

Answer»


SOLUTION :`"Moles of sugar (sucrose)",n_(B)=("Mass of sucrose")/("Gram molar mass")=((40g))/((342g//mol))=0.117 mol`
`"Moles of WATER",n_(A)=("Mass of water")/("Gram molar mass")=((360G))/((18g//mol))=20 mol`
`"Mole fraction of water"(X_(A))=n_(A)/(n_(A)+n_(B))=((20 mol))/((20 mol)+(0.117 mol))=0.9942`
`"Vopour pressure of solution"(P_(A))=P_(A)^(@)x_(A)=20mmxx0.9942=19.884 mm.`


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