1.

Assuming Rydberg constant (R_(H)) to be 109670 cm^(- 1), the longest wavelength line in the Lyman series of the hydrogen spectrum is

Answer»

`1215.8Å`
`1025.8Å`
`972.6Å`
`949.8Å`

Solution :Longest wavelength means smallest wave number. In Lyman series, it is for JUMP from `n_(2) = 2` to `n_(1) = 1`
i.e., `barv=109670(1/(1^(2))-1/(2^(2)))=109670xx3/4=82252.5cm^(-1)`
`lamda=1/v=1/(82252.5cm^(-1))`
`=1215.8xx10^(8)cm=1215.8 Å`


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