1.

Assuming petrol is isooctane (C_8 H_18) and has a density of 0.8 g mL^(-1) 1.425 litres of petrol on complete combustion will consume

Answer»

100 moles of `O_2`
125 moles of `O_2`
150 moles of `O_2`
175 moles of `O_2`

Solution :Wt. of 1.425 litres of petrol = `1.425 xx 1000 xx 0.8 G = 1140` g
Now , the combustion equation is ,
`underset(114 g) (C_(8) H_(18)) + underset(25//2 "moles") (25//2 O_(2)) to 8 CO_(2) + 9 H_2 O`
114 g of petrol requires `O_2 = 25//2` moles
`therefore` 1140 g of petrol will require
`O_2 = (25)/(2) xx (1140)/(114) = 125` moles


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