1.

Assuming fully decomposed, the volume of CO_2released at N.T.P. on heating 9.85 g of BaCO_3(atomic mass of Ba = 137) will be

Answer»

0.84 L
2.24 L
4.06 L
1.12 L

Solution :`BaCO_3 overset("heat")(to) BaO+ CO_2`
Mol. Mass of `BaCO_3 = 137+ 12 +3XX 16 = 197`
197 g of `BaCO_3` on heating GIVES `CO_2 = 22.4L`
9.85 g of `BaCO_3` on heating GIVE
`CO_2 = (22.4 xx 9.85)/(197) = 1.12 L`


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