Assuming consatant retardation of metal ball moving inside water thr b

1.	Assuming consatant retardation of metal ball moving inside water thr ball loses 25% of its speed in 35 cm in a straight line . How much further will it travel before stopping ?
Answer» <P>Answer: Explanation:Let initial VELOCITY of bullet is u , A/C to question, bullet loses25% of its speed while traveling INSIDE a wooden blocks. means final velocity = u -25 % of u = u - u/4 = 3u/4 Now, use formula, v² = u² + 2aS Here, v = 3u/4, S = 14cm ∴ (3u/4)² = u² + 2a(14) ⇒9u²/16 - u² = 28a ⇒ - 7u²/16 = -28a ⇒ a = -u²/64 Let total distance covered by bullet before stopping is x = 14 + P where P is distance covered by bullet after covering 14cm. Now, use formula, v² = u² + 2as here, v = 0, a = -u²/64 ∴ 0 = u² - 2(u²/64)x x = 32 cm So, P = 32 - 14 = 18cm HENCE, bullet further travel 18cm before stopping.

Assuming consatant retardation of metal ball moving inside water thr ball loses 25% of its speed in 35 cm in a straight line . How much further will it travel before stopping ?

Answer»

<P>Answer:

Explanation:Let initial VELOCITY of bullet is u ,

A/C to question,

bullet loses25% of its speed while traveling INSIDE a wooden blocks.

means final velocity = u -25 % of u = u - u/4 = 3u/4

Now, use formula,

v² = u² + 2aS

Here, v = 3u/4, S = 14cm

∴ (3u/4)² = u² + 2a(14)

⇒9u²/16 - u² = 28a

⇒ - 7u²/16 = -28a

⇒ a = -u²/64

Let total distance covered by bullet before stopping is x = 14 + P

where P is distance covered by bullet after covering 14cm.

Now, use formula, v² = u² + 2as

here, v = 0, a = -u²/64

∴ 0 = u² - 2(u²/64)x

x = 32 cm

So, P = 32 - 14 = 18cm

HENCE, bullet further travel 18cm before stopping.

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