1.

Assuming complete ionisation, the pH of 1.0 M HCl is 1. The molarity of H_(2)SO_(4) with the same pH is

Answer»

0.2
0.1
`2.0`
0.05

Solution :PH = 1 means `[H^(+)] = 10^(-1) M`
Hence `[H_(2)SO_(4)] = (10^(-1))/(2) = (1)/(20) =0.05 M`.


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