1.

Assumeideal gas behaviour for all the gasconsidered &vibrationaldegreesof freedomto be active. Separatedequimolar sampleof He, H_(2), SO_(2) & CH_(4) weresubjectedto atwo stepprocess as mentioned. Initially all areat samestate of tempreature&prssure.Step-ItoAll undergo reversible adiabaticexpansion to attainsamefinal volume, which is doublethe original volume thereby causingthe decreases in their temperature .Step -II toAfterstep I allare given appropriate amount of heatisochoricallyto restore the Mark the correct option(s).

Answer»

Due to step -I only, thedecrease in thetempreaturewill be maximumfor `CH_(4)`
During step II, heatgiven will be maximum for `CH_(4)`
There will beno changein internalenergy for any of the gas afterboththe STEPS ofprocess arecompleted.
The P-Vgraph of `CH_(4)` & `SO_(2)`will besame.

Solution :`because`Idealgas & initial& final temperatureare same
`because DelatE= 0 ` for all
`because` (C) is correct
Also`because|W|` ismaximum for `CH_(4)` is stepI & OVERALL
`DeltaE =0 because |q|` for `CH_(4)` will be maximum
`because` option(B) is correct
Sinceafterstep I, all havesame volume , same MOLES &PRESSURE of `CH_(4)`is highest `because`Temperatureof
`CH_(4)`will be highest& sinceinitialit issame
`because` decrease in temperaturewill beleast
`because` option (A) is incorrect
`because gamma ` for the `SO_(2)`& `CH_(4)`is different (due tovibrational degree of freedom )
`because` graphis different
`because` option (D) is incorrect
`because` option (B), (C)


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