1.

Assume that the only change in volume is due to the production of hydrogen and calculate the work done in joules when 2.0 moles of Zn dissolve in hydrochloric acid, giving H_(2) at 35^(@)C and 1 atm. Zn(s)+2HCl(aq) to ZnCl_(2)(aq)+H_(2)(g)

Answer»


SOLUTION :`[W=-pDeltaV=-Deltan_(H_(2))RT]`


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