Assume that if the earth were made of lead of relative density 11.3, then what would be the value of acceleration due to gravity on the earth surface ?

Assume that if the earth were made of lead of relative density 11.3, t

1.	Assume that if the earth were made of lead of relative density 11.3, then what would be the value of acceleration due to gravity on the earth surface ?
Answer» Solution :Since, DENSITY of earth can be given as `RHO=` Relative density `xx` density of water `=11.3 xx 10^(3) "kgm"^(-3)` `:.` Acceleration due to GRAVITY on the earth's surface, `g=(GM)/(R^(2))=(G)/(R^(2)).(4)/(3)piR^(3).rho` `=(4)/(3)xx(22)/(7)xx6.67xx10^(-11)xx6.4 xx10^(6)xx11.2xx10^(3)` `=22.21 MS^(-2)`