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assume that atomic weight of a metal 'M' to be 56,find the empirical formula of its oxide containing 70% of M |
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Answer» weight of metal M = 56in an oxide, metal is 70% by mass and so oxygen is 30% by mass.let there be n ATOMS of oxygen PER 1 atom of metal.Then proportion of the masses of metal and oxygen : 56 : n * 16 = 70 : 30 16 n = 56 * 30 / 70 n = 24/16 = 1.5There are two atoms of metal for 3 atoms of Oxygen.: M2 O3 |
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