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Assume liquefied petroleum gas (LPG) is a 50-50 (by mole) mixture of n-pentane and n-butnane.Calculate the calorific value (in `KJ//"mol"`) of gas available form a newly filled cylinder. Give your answer divide by 100. `{:( ,n-"butane",C_4H_10 n-"pentane" C_6H_12),("Vapour pressure",1800 "Torr",600 "Toor"),("Calorific value ",2800 kJ//"mol",3600 kJ//"mol"):}` |
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Answer» Correct Answer - 30 KJ/mol, increase 30 kJ/mol , increase First of all we find mole fractions in liquid mixture, let mixture is 100 mole So moles of pentane=50 moles of Butane=50 So, `X_("pentane")=0.5 " " X_("Butane")=0.5` `P_T=600xx0.5+1800xx0.5=1200` `Y_("pentane")=300/1200=1/4 " " Y_("Butane")=900/1200=3/4` Calorific value `=3600xx1/4+2800xx3/4`=3000 kJ/mol During use `Y_("pentane") " " "calorific value" uarr` |
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