Assume liquefied petroleum gas (LPG) is a 50-50 (by mole) mixture of n-pentane and n-butnane.Calculate the calorific value (in KJ//"mol") of gas available form a newly filled cylinder. Give your answer divide by 100. {:(,n-"butane",C_4H_10n-"pentane" C_6H_12),("Vapour pressure",1800 "Torr",600 "Toor"),("Calorific value ",2800 kJ//"mol",3600 kJ//"mol"):}

Assume liquefied petroleum gas (LPG) is a 50-50 (by mole) mixture of n

1.	Assume liquefied petroleum gas (LPG) is a 50-50 (by mole) mixture of n-pentane and n-butnane.Calculate the calorific value (in KJ//"mol") of gas available form a newly filled cylinder. Give your answer divide by 100. {:(,n-"butane",C_4H_10n-"pentane" C_6H_12),("Vapour pressure",1800 "Torr",600 "Toor"),("Calorific value ",2800 kJ//"mol",3600 kJ//"mol"):}
Answer» Solution :30 kJ/mol , INCREASE First of all we find mole fractions in LIQUID mixture, let mixture is 100 mole So moles of PENTANE=50 moles of Butane=50 So,`X_("pentane")=0.5 " " X_("Butane")=0.5` `P_T=600xx0.5+1800xx0.5=1200` `Y_("pentane")=300/1200=1/4 " " Y_("Butane")=900/1200=3/4` Calorific VALUE `=3600xx1/4+2800xx3/4`=3000 kJ/mol During use `Y_("pentane") " " "calorific value" uarr`