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Assign reasns for the following (i)Sulphur vapour is paramagnetic, (ii) Ammonia (NH_(3)) has greater affinity for protons than phosphine (PH_(3)). (iii) The negative value of electron gain enthalphy of fluorine is less than that of chlorne. (iv) SF_(6) is much lessreactive than SF_(4). (v) Of the gases only xenon is know the form well-established chemical compounds |
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Answer» Solution :(i)In vapour STATE sulphur partly as `S_(2)` molecule which has two unpaired electrons in the antibonding `pi^(**)` orbtitals like ` O_(2)` and hence it exhibits parmagnetism (iii) When `NH_(3) or PH_(3)` accepts a proton, and addtional N-H or P-H bond is formed `H_(3)N:+H^(+)rarrNH_(4)^(+) and H_(3):+H^(+)rarrPH_(4)^(+)` Due to the bigger size of P than, N, thanP-H bond is weaker .As a result `PH_(3)` has less tendency than `NH_(3)` to accept a proton. Therefore,`NH_(3)`, has higher proton affinity than`PH_(3)` (iii) The electron GAIN enthalphy of flurin is less negative than that of chlorine due to that there is strong repulsion of electrons (iv)In `SF_(6)` sex F atom protect the sulphur atom from attack by the reagent to such adn extent tht enven thermodynamicallymsot favourable reaction like hydrolysis do not occur. Nut in `SF_(4)`,is not sterically protected sicne ist is surrounded by only FOUR F atoms, hence `SF_(4)`, undergoes hydrolysis (v) Exepct radon which is radioactive Xe has least IONISATION energy among noble GASSES and hence it is readity forms chemical compounds particularly with oxygen and flurine. |
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