.Assertion: When I P+ Q I = I P- QI, then P must be perpendicular to Q. Reason: The relation will hold even when Q is a null vector. noooo spaaammmm idiottts

.Assertion: When I P+ Q I = I P- QI, then P must be perpendicular to Q

1.	.Assertion: When I P+ Q I = I P- QI, then P must be perpendicular to Q. Reason: The relation will hold even when Q is a null vector. noooo spaaammmm idiottts
Answer» LET, β be the angle between VECTORS P and Q.Now, vectors Q and -Q are having same magnitude; but they act in opposite directions.So, angle between vectors P and -Q = (180° - β).And, \|-Q\| = \|Q\|.\|P + Q\|^2 = \|P\|^2 + \|Q\|^2 + 2 * \|P\| * \|Q\| * (COS β)And,\|P - Q\|^2 = \|P\|^2 + \|Q\|^2 + 2 * \|P\| * \|Q\| * cos (180° - β).So, cos β = cos (180° - β) = - cos βSo, β = 90°.

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.Assertion: When I P+ Q I = I P- QI, then P must be perpendicular to Q. Reason: The relation will hold even when Q is a null vector. noooo spaaammmm idiottts​

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.Assertion: When I P+ Q I = I P- QI, then P must be perpendicular to Q. Reason: The relation will hold even when Q is a null vector. noooo spaaammmm idiottts