Assertion: I Daniell cell, if concentrations of Cu^(2+) ions and Zn^(2+) ions are doubled, emf of the cell will be doubled. Reason: If concentration of ions in contact with the metal is doubled, the electrode potential is doubled.

Assertion: I Daniell cell, if concentrations of Cu^(2+) ions and Zn^(2

1.	Assertion: I Daniell cell, if concentrations of Cu^(2+) ions and Zn^(2+) ions are doubled, emf of the cell will be doubled. Reason: If concentration of ions in contact with the metal is doubled, the electrode potential is doubled.
Answer» If both assertion and reason are true, and reason is the true explanation of the assertion if both assertion and reason are true, but reason is not the true explanation of the assertion. if assertion is true, but reason is false. If both assertion and reason are false. Solution :CORRECT A. `Zn+CU^(2+)toZn^(2+)+Cu,E_(cell)=E_(cell)^(@)-(RT)/(nF)"ln"([Zn^(2+)])/([Cu^(2+)])` Thus, if `[Zn^(2+)]` and `[Cu^(2+)]` are DOUBLED, there is no effect of emf. Correct R. `Cu^(2+)+2e^(-)toCu,E=E^(@)-(RT)/(nF)"ln"(1)/([Cu^(2+)])` Thus, if `[C^(2+)]` is doubled, E is not doubled.