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Assertion : [Cr(H_(2)O)_(6)]Cl_(2) and [Fe(H_(2)O)_(6)]Cl_(2) are reducing in nature. Reason : Unpaired electrons are present in their d-orbitals.

Answer»


SOLUTION :Correct EXPLANATION. Cr is present as `Cr^(2+)` which can undergo oxidation to `Cr^(3+)` and Fe is present as `Fe^(2+)` which can undergo oxidation to `Fe^(3+)` (`H_(2)O` is a weak ligand in both).


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