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Assertion At height 20 m from ground , velocity of a projectile is `v = (20 hati + 10 hatj) ms^(-1)`. Here, `hati` is horizontal and `hatj` is vertical. Then, the particle is at the same height after 4s. Reason Maximum height of particle from ground is 40m (take, `g = 10 ms^(-2))`A. If both Asseration and Reason are correct and Reason is the correct explanation of AssertionB. If both Assertion and Reason are correct but Reason is not the correct explanation of AssertionC. If Assertion is true but Reason is falseD. If Assertion is false but Reason is true |
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Answer» Correct Answer - B `t = (2u_(y))/(g) = (2xx 20)/(10) = 4s` `H = 20 +(u_(y)^(2))/(2g) = 20 +((20)^(2))/(2 xx 10) = 40m` |
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