1.

Assertion :""^(22)_(11)Na emits a position giving ""^(22)_(12)Mg Reason : In beta^+ emission neutron is transformed into proton.

Answer»


Solution :`._(11)Na^(22) rarr ._(12)Mg^(22) + ._(-1)beta^(0)`
THUS this change involves a `beta`-particle EMISSION and not a positron. Also, proton emission converts proton into neutron as : `._(1)P^(1) rarr ._(0)n^(1) + ._(+1)beta^(0)`


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