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Asin ^3x + bcos^3x = sinxcosx Then find a^2 + b^2 when asinx = bcosx |
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Answer» Answer: GIVEN asinx = bcosx ........(1)asin^3x + bcos^3x = SINX.cosxasinx sin^2x+bcos^3x=sinxcosxbcosx sin^2x+bcos^3x=sinxcosxbcosx(sin^2x+cos^2x) = sinx.cosxbcosx.1 = sinx.cosx thenB = sinxsinx = b substitue this in (1)a.b = b cosx thencosx = asubstitute sinx = b and cosx = a inasin^3x+bcos^3x = sinx.cosxa.b^3 + b.a^3 = a.bab(a^2+b^2) = ab thusa^2+b^2 = 1Thank youFollow me |
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