1.

As shown in figure the tension in the horizontal cord is 30n the weight w and the tension in the string oa in newton are ​

Answer»

From the FIGURE Tsin30∘=30Tsin30∘=30….(i) Tcos30∘=WTcos30∘=W ….(II) By SOLVING EQUATIONS (i) and (ii), we GET W=30√3NW=30root3Nand T=60N



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