1.

As dillution takes place

Answer»

oxidation potential decreases
reduction potential increases
oxidation potential increases
cell potential may increases

Solution :From Nemst EQUATION
`E_(M^(2+)//M)=E_(M^(1+//M)^(@)- (2.303)/(NF) log (1)/([M^(n+)])`
`rArr E_(M^(1+)//M)=E_(M^(1+)//M)^(@)+(2.303)/(nF) log [M^(n+)]`
`E^(M//M^(1+))=E_(M//M^(2+))^(@)-(2.303)/(nF) log [M^(n+)]`
Thus on increasing the concentralion keeping olher factors conslant.
Reduction potenial `(E_(M^(1+)//M))` increases oxidation potential `(E_(M//M^(+))` decreases while on dilution reducion polential decreases, oxidation potential increases. Hence choices (C) and (D) are correct while (A) and (B) are INCORRECT.


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