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Arun swims in a 135 m long pool. He covers 270 m in 1.5 minutes from one end to the other and back along the same straight path. What is the average velocity of Arun? |
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Answer» 45 NHeight = 4m\boxed{\rm{\red{Find \longrightarrow }}} Find⟶ gravitational potential energy of this object?\boxed{\rm{\pink{FORMULA \ used \longrightarrow }}} Formula used⟶ \SF{\red{ PE_G= mg \Delta h}}PE G =mgΔhwhere,\sf{PE_G}PE G =potential energy due to gravityg=acceleration due to gravitym=mass\sf{\Delta h}Δh = distance above a surface\boxed{\rm{\PURPLE{SoLution \longrightarrow }}} SoLution⟶ we knowF= m a here, {a= g}so the value of mg= FBY Putting value in the formula we get,\sf{PE_G= 45 \times 4}PE G =45×4\sf{ PE_G= 180}PE G =180\underline{\bf{\therefore Gravitational \ Potential \ energy \ = 180 kg m^2 /s^2}} ∴Gravitational Potential energy =180kgm 2 /s 2 __________________________ |
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