Saved Bookmarks
| 1. |
Arrives at lens equation from lens maker's formula . |
|
Answer» SOLUTION :Fromrefraction through a double convex lens the RELATION between the object DISTANCE u, image distance `v_(1)` and radius of curvature `R_(1)` as `(mu_(2))/(v_(1))-(mu_(1))/(u)=(mu_(2)-mu_(1))/(R_(2))` The relationbetween the object distance `v_(1)` image distance v and radius of curvature `R_(2)`canbe `(mu_(1))/(v)-(mu_(2))/(v_(1))=(mu_(1)-mu_(2))/(R_(2))` Adding EQUATION (1) and (2) `(mu_(1))/(v)-(1)/(u)=(mu_(2)-mu_(1))[(1)/(R_(1))-(1)/(R_(2))]` If the object is placed at infinty `(u = oo)`, the image will be FORMED at the focus,i.e. v = f `(1)/(f)=((mu_(2)-mu_(1))/(mu_(1)))[(1)/(R_(1))-(1)/(R_(2))]` This is len.s maker.s formula. When the lens is placed in air `mu_(1) = 1 and mu_(2) = mu` Equation (4) becomes, `(1)/(f)=(mu_(2)-mu_(1))[(1)/(R_(1))-(1)/(R_(2))]` Fromequation (3) and (4), we have `(1)/(v)-(1)/(u)=(1)/(f)` This is the len.s equation |
|