Saved Bookmarks
| 1. |
Arrannge the following is order of decreasing acid strength: CH_(3)OH,H_(2)O,C_(6)H_(5)OH |
|
Answer» Solution :DUE to +I-effect of the `CH_(3)` group, the electron density is the O-H BOND of `CH_(3)OH` is more than that in water, H-OH. Therefore, O-H bond in `CH_(3)OH` is stronger and hence more difficult to break than O-H bond in `H_(2)O` and hence `CH_(3)OH` is a weaker aciid than `H_(2)O`. In contrast, phenoxdie ion (left after the removal of a proton) is stabilized by resonance, whereas methoxide ion (left the removal of a proton from `CH_(3)OH`) is not. therefore, `C_(6)H_(5)OH` is a stronger acid than `CH_(3)OH`. thus, the overal acidic STRENGTH decreases in the order: `C_(6)H_(5)OH gt H_(2)O gt CH_(3)OH`. |
|