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Arrange thhe following compounds in increasing order of S_(N)1 reactivity. (a) ClCH_(2)CH=CHCH_(2)CH_(3),CH_(3)C(Cl)+CHCH_(2)CH_(3),CH_(3)CH=CHCH_(2)CH_(2)Cl (b) CH_(3)CH_(2)Br,CH_(2)=CHCH(Br)CH_(3),CH_(2)=CHBr,CH_(3)CH_(3)CH(Br)CH_(3). |
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Answer» SOLUTION :(a) `CH_(3)C(Cl) = CHCH_(2)CH_(3), CH_(3)CH = CHCH_(2)CH_(2)Cl, ClCH_(2)CH = CHCH_(2)CH_(3)` (b) `CH_(2) = CHBr, CH_(3)CH_(2)Br, CH_(3)CH(Br)CH_(3), CH_(2) = CHCH(Br)CH_(3)` (c) `CH_(3)CH_(2)CH_(2)Cl, (CH_(3))_(2)CHCL, (CH_(3))_(3)C Cl, C_(6)H_(5)C(CH_(3))_(2)Cl` |
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