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Arrange the following solutions in increasing order of their van't Hoff factor : 0.1M CaCl_(2), 0.1 M KCl, 0.1 M Al_(2)(SO_(4))_(3), 0.1 M C_(12)H_(22)O_(11) |
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Answer» Solution :GREATER the number of ions produced on DISSOCIATION, greater is the van't Hoff FACTOR. Hence, the ORDER is `0.1M C_(12)H_(22)O_(11) LT 0.1 M KCl lt 0.1 M CaCl_(2) lt 0.1 M Al_(2)(SO_(4))_(3)` |
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