1.

Arrange the following in the order of increasing mass (atomic mass: O = 16, Cu = 63, N = 14) I. one atom of oxygenII. one atom of nitrogen III. 1 xx 10^(-10_mole of oxygen IV. 1xx 10^(-10)mole of copper

Answer»

II lt I lt III lt IV
I lt II lt III lt IV
III lt II lt IV ltI
IV lt II lt III lt I

Solution :I.Mass of 1 atom of oxygen
` = (16)/(6.022 xx 10^23)`
`= 2.66 xx 10^(-23) g `
II. Mass of 1 atom of nitrogen ` = (14)/(6.022 xx 10^23)`
` = 2.32 xx 10^(-23)g `
III. Mass of `1 xx 10^(-10) ` mol of oxygen
`= 16 xx 10^(-10) g`
IV. Mass of ` 1xx 10^(-10) ` mol of copper ` = 63 xx 10^(-10) g `
`therefore ` order of INCREASING atomic mass :
`II lt II lt III lt IV`


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