Arrange the following in order of their increasing masses in grams? (i) One atom of silver (ii) One gram-atom of nitrogen (iii) One mole of calcium (iv) One mole of oxygen molecules (v) 10^(23) atoms of carbon and (vi) One gram of iron.

Arrange the following in order of their increasing masses in grams? (

1.	Arrange the following in order of their increasing masses in grams? (i) One atom of silver (ii) One gram-atom of nitrogen (iii) One mole of calcium (iv) One mole of oxygen molecules (v) 10^(23) atoms of carbon and (vi) One gram of iron.
Answer» Solution :(i) 1 mole of Ag atoms = 108 g `=6.022xx10^(23)` atoms i.e., mass of `6.022xx10^(23)" atoms of Ag = 108 g"therefore"Mass of 1 atom of Ag"=(108)/(6.022xx10^(23))=1.793xx10^(-22)g` (ii) Mass of one gram atom of N = At. Mass of grams = 14.0 g (iii) Mass of one mole of CA = At. Mass in grams = 40.0 g (IV) Mass of one mole of oxygen molecules = Mol. mass in grams = 32.0 g (v) 1 mole of C atoms = 12 g `=6.022xx10^(23)` atoms, i.e., Mass of `6.022xx10^(23)` atoms of C = 12.0 g `therefore"Mass of " 10^(23)" atoms of C"=(12)/(6.022x10^(23))xx10^(23)=1.993g` (vi) Mass ofiron = 1.0 g (Given) Thus, the ORDER of increasing MASSES is : One atom of silver lt one gram of iron lt `10^(23)` atoms of carbon lt one gram-atom of nitrogen lt one mole of oxygen lt one mole of calcium.