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Arrange the following in order of increasing molar conductivity. (i) Mg[Cr(NH_(3))(Cl)_(5)] (ii)[Cr(NH_(3))_(5)Cl]_(3)[CoF_(6)]_(2) (iii) [Cr(NH_(3))_(3)Cl_(3)] |
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Answer» SOLUTION :These complexes can ionise in solution as : `MG[Cr(NH_(3))(Cl)_(5)]=Mg^(2+)+[Cr(NH_(3))(Cl)_(5)]^(2-)` `[Cr(NH_(3))_(5)Cl]_(3)[CoF_(6)]_(2)=[Cr(NH_(3))_(5)Cl]^(2+)+[CoF_(6)]^(3-)` `[Cr(NH_(3))_(3)Cl_(3)]=` does not ionize As the number of IONS in solution increases, their molar conductivity also increases. Therefore, conductivity follows the order : `[Cr(NH_(3))_(3)Cl_(3)] lt [Cr(NH_(3))_(5)Cl]_(3)[CoF_(6)]_(2) lt Mg[Cr(NH_(3))(Cl)_(5)]` |
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