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Arrange the following in order of decreasing N - O bond length `NO_(2)^(-),NO_(2)^(-),NO_(3)^(-)` |
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Answer» This is on account of the difference in the hybridistain states of the nitrogen atoms in the two ions. `NO_(2)^(-) , H=1//2[5+0-0+1]=3 (sp^(2)` hybridisation) `NO_(2)^(+) , H=1//2[5+0-1+0]=2` (sp hybridisation) |
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