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Arrange the following : In increasing order of boiling point : C_(2)H_(5)OH, (CH_(3))_(2)NH, C_(2)H_(5)NH_(2). |
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Answer» Solution :Electronegativity of O is HIGHER than that of N, therefore, alcohols from stronger H-bonds than amines. In other words, the boiling points of alcohols are higher than those of amines of comparable molecular masses. Therefore, the boiling point of `C_(2)H_(5)OH` is higher than those of `(CH_(3))_(2)NH" and "C_(2)H_(5)NH_(2)`. Further, the extent of H-bonding depends upon the number of H-atoms on the N-atom. Therefore, `1^(@)` amines with two H-atoms on the N-atom have higher boiling points than `2^(@)` amines (of comparable molecular mass) having only one H-atom. The boiling point of `C_(2)H_(5)NH_(2)` is, therefore, higher than that of `(CH_(3))_(2)NH`. Thus, the boiling points of the given three compounds increase in the order : `""(CH_(3))_(2)NH lt C_(2)H_(5)NH_(2) lt C_(2)H_(5)OH`. |
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