1.

Arrange the following in increasing order of basicity: H_(2)O,OH^(-),CH_(3)OH,CH_(3)O^(-)

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Solution :Consider the reaction, `CH_(3)O^(-)+H_(2)OtoCH_(3)OH+OH^(-)`. Since a stronger BASE displaces a weaker base from its COMPOUNDS, THEREFORE, `CH_(3)O^(-)` is a stronger base than `OH^(-)` ion and `CH_(3)OH` is a stronger base than `H_(2)O`. Thus, the order of INCREASING basicity is: `H_(2)O,CH_(3)OH,OH^(-),CH_(3)O^(-)`


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