Saved Bookmarks
| 1. |
Arrange the following : (i) In decreasing order of pKb values : C_(2)H_(5)NH_(2), C_(6)H(5)NHCH_(3), (C_(2)H_(5))_2NH and C_(6)H_(5)NH(2) (ii) In increasing order of basis strength : (a) Aniline , p-nitroaniline and p-toluidine (b) C_(6)H_(5)NH_(2), C_(6)H_(5)NHCH_(3), C_(6)H_(5)CH_(2)NH_(2) (iii) In decreasing order of basis strength: C_(6)H_(5)NH_(2), C_(6)H_(5)NH(CH_(3))_(2), (C_(2)H_(5))_(2)NH, CH_(3)NH_(2) (iv) Decreasing order of basis strength in gas phase : C_(2)H_(5)NH_(2), (C_(2)H_(5))_(2)NH, (C_(2) H_(5))_(3)N andNH_(3) (v) Increasing order of boiling point : C_(2)H_(5)OH, (CH_(3))_(2)NH, C_(2)H_(5)NH_(2). |
|
Answer» Solution :(i) `C_(6)H_(5)NH_(2) GT C_(6)H_(5)NHCH_(3)gt C_(2)H_(5)NH_(2)gt (C_(2)H_(5))_(2)NH` (ii) (a) p-nitroaniline LT aniline lt p-toluidine (b) `C_(6)H_(5)NH_(2) lt C_(6)H_(5)NHCH_(3) lt C_(6)H_(5)CH_(2)NH_(2)` (III) `(C_(2)H_(5))_(2)NH gt CH_(3)NH_(2) gt C_(6)H_(5)N(CH_(3))_(2) gt C_(6)H_(5)NH_(2)` (iv) `(C_(2)H_(5))_(3)N gt (C_(2)H_(5))_(2)NH gt C_(2)H_(5)NH_(2) gt NH_(3)` (v) `(CH_(3))_(2)NH lt C_(2)H_(5)NH_(2) lt C_(2)H_(5)OH ` |
|