1.

Arrange the following compounds in increasing order of C-OH bond length: methanol, phenol, p-ethoxyphenol

Answer»

`" phenol" LT "METHANOL" lt "p-methoxyphenol"`
`"methanol" lt"p-methoxyphenol" lt " phenol"`
`" phenol" lt "p-methoxyphenol"lt "methanol"`
`"methanol" lt" phenol" lt "p-methoxyphenol"`

Solution :In methanol, there is no resonance. In phenol, there is resonance. In p-Ethoxyphenol, there is resonance involved but the involvement of lone PAIR of oxygen in OH group is poor as compared with phenol due to the presence of lone pair oxygen in `OCH_(3)` group which are also involved in resonance.
So, partial double bond CHARACTER develops in C-OH bond of phenol and p-ethoxyphenol but in case of p-ethoxyphenol, resonance is poor as compared to phenol. So, bond LENGTH follows the order : `"methanol" gt "p-ethoxyphenol" gt "phenol"`


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