1.

Arrange the following: CH_(3)CH_(2)CH_(2)Cl (I),CH_(3)CH_(2)CHClCH_(3)(II),(CH_(3))_(2)CHCH_(2)Cl(III) and (CH_(3))_(3)C-Cl(IV) in order of decreasing tendency towards S_(N)2 reaction

Answer»

IgtIIIgtIIgtIV
IIIgtIVgtIIgtI
IIgtIgtIIIgtIV
IVgtIIIgtIIgtI

Solution :The ORDER of reactivity in `S_(N)2` reactions is:
`1^(@) gt 2^(@) gt 3^(@)`,
further, amongst `1^(@)` ALKYL halides, unsubstituted alkyl halides are more reactive than SUBSTITUTED alkyl hlaides. Thus, the overall decreasing reactivity in `S_(N)2` reaction is:
i.e., `underset(I)(CH_(3)CH_(2)CH_(2)CL(1^(@))) gt underset(III)((CH_(3))_(2)CHCH_(2)Cl(1^(@))) gt underset(II)(CH_(3)CH_(2)CHClCH_(3)(2^(@))) gt underset(IV)((CH_(3))_(3)C-Cl(3^(@)))`


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