Arrange each set of compounds in orderr of increasing boiling points. (i) Bromomethane, bromoform, chloromethane, dibromomethane. (ii) 1-Chloropropane, isopropyl chloride, 1-chlorobutane.

Arrange each set of compounds in orderr of increasing boiling points.

1.	Arrange each set of compounds in orderr of increasing boiling points. (i) Bromomethane, bromoform, chloromethane, dibromomethane. (ii) 1-Chloropropane, isopropyl chloride, 1-chlorobutane.
Answer» Solution :(i) For the same ALKYL group, boiling point increases with the size of the halogen atom. Therefore, boiling point of BROMOMETHANE is HIGHER than that of chloromethane. Further, the boiling points increase as the number of halogen ATOMS increases. therefore, the boiling point of bromoform with three Br atoms is the highest, followed by dibromomethane with two Br atoms while bromomethane with oe Br atom is the lowest. combining al the arguments presented above, the boiling points of the four COMPOUNDS discussed above increase in the order: chloromethaneltbromomethaneltdibromomethaneltbromoform. (ii) For the same halogen, boiling point increases as the size of the alkyl group increases. therefore, the boiling point of 1-chlorobutane is higher than those of 1-chloropropane and isopropyl chloride. further, the boiling point decreases as the braching increases, therefore, the boiling point of 1-chloropropane is higher than that of isopropyl chloride. combining these two arguments, the boiling points of the three compounds discussed above increase in the order: Isopropyl chloridelt1-chloropropanelt1-chlorobutane.