1.

Area of the path around a square field is 425 m² Find the width of the path if the side of the square is 40 m.​

Answer»

Let the width of the PATH be x m.

Now, according to the question

(40 + 2x)² - 40² = 425

40² + 160x + 4x² - 40² = 425

4x² + 160x - 425 = 0

(2x)² + 2(2x)(40) +1600 - 2025 = 0

(2x + 40)² = 2025

2x + 40 = +- 45

x = 5/2, -85/2

Since it can't be negative

So, the REQUIRED width of the path is 5/2 m or 2.5 m

Arey kyu nahi remeber karega?

Voh earthworm waala question mein BHI toh BRAINLIEST MILA na tume aur is waale mein bhi :)



Discussion

No Comment Found

Related InterviewSolutions