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Area of the path around a square field is 425 m² Find the width of the path if the side of the square is 40 m. |
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Answer» Let the width of the PATH be x m. Now, according to the question (40 + 2x)² - 40² = 425 40² + 160x + 4x² - 40² = 425 4x² + 160x - 425 = 0 (2x)² + 2(2x)(40) +1600 - 2025 = 0 (2x + 40)² = 2025 2x + 40 = +- 45 x = 5/2, -85/2 Since it can't be negative So, the REQUIRED width of the path is 5/2 m or 2.5 m Arey kyu nahi remeber karega? Voh earthworm waala question mein BHI toh BRAINLIEST MILA na tume aur is waale mein bhi :) |
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