Area of base of cyclinder is 154 sq. M and it ht. is 15 m .find volume

1.	Area of base of cyclinder is 154 sq. M and it ht. is 15 m .find volumeO
Answer» Given : AREA of base of cyclinder = 154 m² Height of cylinder = 15 m To find : volume Formula used : $\sf v = \pi {r}^{<klux>2</klux>} h$ where :- r = RADIUS of base πr² = area of base h = height of cylinder Therefore , if we take πr² (area of base) = a we get :- $\sf v = a \times h$ Solution : Area of base of cyclinder = 154 m² Height of cylinder = 15 m Now we will find volume :- $\sf \implies v = a \times h$ Put :- a = 154 h =15 $\sf \implies v = 154 \times 15 \: {m}^{ 3}$ $\sf \implies v = 2310 {m}^{ 3}$ Answer : Volume of given cylinder = 2310 m³ _____________________ Learn more : Volume of cylinder = πr²h T.S.A of cylinder = 2πrh + 2πr² Volume of cone = ⅓ πr²h C.S.A of cone = πrl T.S.A of cone = πrl + πr² Volume of cuboid = l × B × h C.S.A of cuboid = 2(l + b)h T.S.A of cuboid = 2(lb + bh + lh) C.S.A of cube = 4a² T.S.A of cube = 6a² Volume of cube = a³ Volume of sphere = (4/3)πr³ Surface area of sphere = 4πr² Volume of HEMISPHERE = ⅔ πr³ C.S.A of hemisphere = 2πr² T.S.A of hemisphere = 3πr²

Area of base of cyclinder is 154 sq. M and it ht. is 15 m .find volumeO

Answer»

Given :

AREA of base of cyclinder = 154 m²

Height of cylinder = 15 m

To find :

volume

Formula used :

$\sf v = \pi {r}^{<klux>2</klux>} h$

where :-

r = RADIUS of base
πr² = area of base
h = height of cylinder

Therefore , if we take πr² (area of base) = a we get :-

$\sf v = a \times h$

Solution :

Area of base of cyclinder = 154 m²

Height of cylinder = 15 m

Now we will find volume :-

$\sf \implies v = a \times h$

Put :-

a = 154
h =15

$\sf \implies v = 154 \times 15 \: {m}^{ 3}$

$\sf \implies v = 2310 {m}^{ 3}$

Answer :

Volume of given cylinder = 2310 m³

_____________________

Learn more :

Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × B × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Volume of cube = a³

Volume of sphere = (4/3)πr³

Surface area of sphere = 4πr²

Volume of HEMISPHERE = ⅔ πr³

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²