Area of a Trapezium is 160 square CM length of parallel sides are in t

1.	Area of a Trapezium is 160 square CM length of parallel sides are in the ratio 1 ratio 3 if smaller of The parallel sides is 10 cm in length then find the perpendicular distance between them
Answer» LET the parallel side of trapezium be x & 3X cm respectively Area=160 cm^2 Short parallel side=x=10 cm Short parallel side=3x=310 =30 cm 1/2(a+b)h=160 1/2(10+30)h=160 1/240h=160 20h=160 h=160/20 h=8 cm Therefore,perpendicular distance between them is 8 cm.

Area of a Trapezium is 160 square CM length of parallel sides are in the ratio 1 ratio 3 if smaller of The parallel sides is 10 cm in length then find the perpendicular distance between them

Answer»

LET the parallel side of trapezium be x & 3X cm respectively

Area=160 cm^2

Short parallel side=x=10 cm

Short parallel side=3x=3*10 =30 cm

1/2(a+b)*h=160

1/2(10+30)*h=160

1/2*40*h=160

20*h=160

h=160/20

h=8 cm

Therefore,perpendicular distance between them is 8 cm.

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Area of a Trapezium is 160 square CM length of parallel sides are in the ratio 1 ratio 3 if smaller of The parallel sides is 10 cm in length then find the perpendicular distance between them

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