1.

ar (ADEFQ.9, lif the zeroes of the polynomial x2+px + g are double in value to the zeroes of 22-5x-3find the value of p and q

Answer»

For equation 2x^2 - 5x - 3 = 02x^2 - 6x + x - 3 = 02x(x - 3) + 1(x - 3)=0(2x + 1)(x - 3) = 0x = - 1/2, 3

Then zeroes of x^2 + px + q = 0are - 1 and 6Then, -p/1 = - 1 + 6 p = - 5q/1 = - 1*6 = - 6q = - 6



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