1.

Ar(AABC) q5. If AABC AQRP,-and BC-15 cm, then find PR.Ar(AQRP) 4

Answer»

Ar(ABC)/ar(PQR)=K²

K IS CONSTANT

K=3/2

SINCE TRIANGLES ARE SIMILAR

BC/PR=K

PR=BC/KPR=15x2/3

PR=10cm



Discussion

No Comment Found