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Ar(AABC) q5. If AABC AQRP,-and BC-15 cm, then find PR.Ar(AQRP) 4 |
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Answer» Ar(ABC)/ar(PQR)=K² K IS CONSTANT K=3/2 SINCE TRIANGLES ARE SIMILAR BC/PR=K PR=BC/KPR=15x2/3 PR=10cm |
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