1.

Apply VSEPR theory to deduce the structures of XeF_4 and XeF_6

Answer»

Solution : `XeF_4` has square PLANAR structure due to the presence of FOUR bonded pairs of ELECTRONS and two lone pairs of electrons.
`XeF_6` has distorted OCTAHEDRAL structure due to the presence of one lone pair of electrons and six bonded pairs of electrons.


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