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Apply Euclid's division algorithm to find HCF of numbers 4052 and 420.chares

Answer»

a = bq + r4052 = 420 × 9 + 272420 = 272 × 1 + 148272 = 148 × 1 + 124148 = 124 × 1 + 24124 = 24 × 5 + 424 = 4 × 6 + 0

HCF(4052, 420) = 4

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420/2=210/2=105/5=21/3=7; 2x2x5x3x7; 4052/2=2026/2=1013



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