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Anybody please answer the question |
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Answer» ong>Answer: If 2x=3y6-z, then 1/x+1/y+1/z is 2x=k k 1/x = 2 Similarly,k 1/x = 3 and k 1/z = 6 = k-1/z = 2×3 =k-1/z = k 1/x × k 1/y = - 1/z = 1/x + 1/y =1/x + 1/y + 1/z =0 |
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