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Any mathematical way to solve this question other than counting. |
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Answer» Yeas there is an EASIER formula. You can use the formula x*{1+2+3+....+n+(n+1)} = x*[(n+1)+(n+2)]/2 Where n is the NUMBER of vertical lines forming a TRIANGLE and x being no of horizontal lines forming a triangle. I can DM you a LINK for similiar question if you want. |
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